Sure Madhu garu! Here's the easy and copyable answer step-by-step:
Given:
- 5 people: P, Q, R, S, T
- All are facing the centre (important)
- P is diametrically opposite to T
- Q has R and T as neighbours
- Only one person is to the right of P
- Only one person is to the left of T
- We need to find the order in anti-clockwise direction starting from R
Step-by-step arrangement:
Let’s arrange them around a circle:
Let’s fix P first.
Since only one person is to the right of P, and all are facing centre, then:
👉 Right of P (facing centre) means clockwise direction.
So if only one person is on P’s right, then P must be sitting at position such that only one person is clockwise to him. That is possible only if P is at position 4 in the circle (see below).
Let’s number positions clockwise as 1–5 for understanding:
Positions (clockwise): 1 → 2 → 3 → 4 → 5
Try P at position 4
Then right of P (clockwise) = position 5
→ only one person is at his right ✅
P is opposite to T, so T must be at position 1.
Now from statement:
Q has R and T as neighbours
T is at position 1
So Q must be at position 2
→ Then R must be at position 3 ✅
Now we are left with one person: S
The only empty position is position 5 → S
So positions are:
1 - T
2 - Q
3 - R
4 - P
5 - S
Now write names in anticlockwise order starting from R (position 3):
R → Q → T → S → P
✅ Final Answer (Anti-clockwise from R):
R, Q, T, S, P
You can copy this easily. If needed in Telugu, I’ll write that too.
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